You can use GeoGebra
to solve systems of inequalities. Type >=
to enter , and <=
to enter .
GeoGebra
Instruction 1
CAS
CAS
under View
in Menu
. Solve
to get an exact solution . Note! If GeoGebra
returns , then the inequality has no solution. If GeoGebra
returns true
, then the inequality is always true. If GeoGebra
returns false
, then the expression is never true for any . If GeoGebra
returns ?
, you have pressed Solve Numerically
. GeoGebra
does not allow this. You must use Solve
.
Example 1
The image below shows what it will look like in GeoGebra
if you solve the inequality by following the instructions above.
GeoGebra
Instruction 2
Graphics View
Graphics View
in View
. Algebra View
and press Enter
. Algebra View
and press Enter
. Intersect
tool and click the two graphs to find any possible intersections. You’re going to use the intersection points later. If you don’t get any intersection points, then your inequality is either always true, or never true. Continue to the next step to find out which one of these is the case for your inequality.
f(x)>g(x)
in Algebra View
. If the inequality contains the symbols or , type f(x)<g(x)
in Algebra View
. Then press Enter
. The solution is the union of all the intervals of the -axis that are covered in blue.
If you didn’t get any intersection points in Step 4, the Graphics View
window should be covered entirely in blue if your inequality is always true (), or not covered at all if it’s never true ().
If you did get intersection points in Step 4, use the -coordinates of the intersection points as the boundaries of the intervals. If the blue area extends indefinitely to the right, use instead, or if it extends indefinitely to the left, use instead. If the equation uses or , use brackets, i.e. at the boundary points, otherwise use regular parentheses, .
The picture shows the area where the graph of lies above the graph of in the coordinate system. This means that the -value of is greater than the -value of in the shaded area. From the image you can see that when .